2c^2-160=0

Solution for 2c^2-160=0 equation:

2c^2-160=0

a = 2; b = 0; c = -160;
Δ = b2-4ac
Δ = 02-4·2·(-160)
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{5}}{2*2}=\frac{0-16\sqrt{5}}{4}
=-\frac{16\sqrt{5}}{4}
=-4\sqrt{5}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{5}}{2*2}=\frac{0+16\sqrt{5}}{4}
=\frac{16\sqrt{5}}{4}
=4\sqrt{5}
$